8x^2+52x+28=0

Solution for 8x^2+52x+28=0 equation:

8x^2+52x+28=0

a = 8; b = 52; c = +28;
Δ = b2-4ac
Δ = 522-4·8·28
Δ = 1808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1808}=\sqrt{16*113}=\sqrt{16}*\sqrt{113}=4\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-4\sqrt{113}}{2*8}=\frac{-52-4\sqrt{113}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+4\sqrt{113}}{2*8}=\frac{-52+4\sqrt{113}}{16}
$